4x^2-28x+3=4x(x-7)

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Solution for 4x^2-28x+3=4x(x-7) equation: 


Simplifying
4x2 + -28x + 3 = 4x(x + -7)

Reorder the terms:
3 + -28x + 4x2 = 4x(x + -7)

Reorder the terms:
3 + -28x + 4x2 = 4x(-7 + x)
3 + -28x + 4x2 = (-7 * 4x + x * 4x)
3 + -28x + 4x2 = (-28x + 4x2)

Add '28x' to each side of the equation.
3 + -28x + 28x + 4x2 = -28x + 28x + 4x2

Combine like terms: -28x + 28x = 0
3 + 0 + 4x2 = -28x + 28x + 4x2
3 + 4x2 = -28x + 28x + 4x2

Combine like terms: -28x + 28x = 0
3 + 4x2 = 0 + 4x2
3 + 4x2 = 4x2

Add '-4x2' to each side of the equation.
3 + 4x2 + -4x2 = 4x2 + -4x2

Combine like terms: 4x2 + -4x2 = 0
3 + 0 = 4x2 + -4x2
3 = 4x2 + -4x2

Combine like terms: 4x2 + -4x2 = 0
3 = 0

Solving
3 = 0

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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